Class 7 Mathematics Assam Jatiyo Bidyalay School Mathematics Book Chapter 1 অখণ্ড সংখ্য়া Question Answer | Class 7 Mathematics AJB | অনুশীলনী 1(A) |

অখণ্ড সংখ্য়া

অনুশীলনী 1(A)

1. মান নিৰ্ণয় কৰা :

 i) 17+(-9)                           

= 17- 9  

= 8

ii) -25+ 13 

=  -12

iii) -8+(-19) 

= -8-19

= -27

iv) (-36)+42 

= -36+42

= 6

v) 63+ (-29) 

= 63-29

=34 

vii) (-38)+(-42) .

= (-38)-42

= -80

2) তলৰ অখণ্ড সংখ্যাবোৰৰ যোগফল উলিওৱাঁ ঃ

(i) 263 আৰু 146

= 263+ 146

= 409

(ii) 315 আৰু -265

= 315+ (-265)

= 315 -265

= 50

(iii) -219 আৰু 300 

= -219+300 

= 81

(iv) -157 আৰু  -385 

= -157+ (-385)

= -157-385 

= -542

(v) -424 আৰু 346 

= -424+346 

=-78

(vi) 275 আৰু -429

= 275+(-429) 

=275-429⇻

= -154

3) তলৰ অখণ্ড সংখ্যাবোৰৰ যোগাত্মক বিপৰীত সংখ্যাবোৰ লিখাঁ ঃ-

(i) 46

Solution: -46 

(ii) -92 

Solution: 92 

(iii) 0

Solution: 0

(iv) -33 

Solution: 33 

(v) 64

Solution: -6

4) বিয়োগ কৰোঁ ঃ

(i) 262ৰপৰা 136 

= 262 -136 

= 126

(ii)175 ৰপৰা 327 

= 175 – 327

=  -152

(iii) 315 ৰপৰা -182

= 315- (-182) 

= 315 +182

= 497

(iv) -286 ৰপৰা 196 

= -286 – 196 

= – 482

(v) -242 ৰপৰা  -305 

.= -242 – (-305

= -242+305

= 63 

(vi) -460 ৰপৰা -525

= -460 -(-525)

= -460+525

= 65

5. খালী ঠাই পূৰ কৰাঁ ঃ

(i) 25 + 16 = 16+25

(ii) {(-25) +17} + (-30) = (-25) + {17 + (-30)}

(iii) -18 +0  = -18 

(iv) 72 + (-72) = 0

(v) -23 +(-17) = -17 + (-23) 

(vi) -29 + 29 = 0

6. সৰল কৰা  ঃ 

(i) 26 – 46 + 29 – 18 

= (26 – 46) + (29 -18 )

= -20 + 11

= -9 

(ii) – 39 + (-14) + 89 -13 + 11

= -39 – 14 + 89 – 13 + 11

= (-39 -14 ) + (89 – 13) + 11

= (-53 +76) +11

= 23+11

= 34

(iii) 52 + (-38) +34 +(-72) +16

= 52 -38 + 34 – 72 + 16

= (52 – 38) + (34 -72) +16 

= 14 + (- 38) +16.

= (14 -38) + 16

= -24 + 16 .

= – 8

(iv) 100 + 432 – 209 – 136 -49

= (100 + 432) -209 – 136 – 49

= (532) -394

= 532 -394 

= 138

(v) – 462 + 139 – 264 + 501 

= (-462 + 139 ) -264 + 501

=  (-323 – 264) + 501

= -587 + 501

= -86

7. a = 16 , b = -22, c = 18 হ’লে তলৰ ধৰ্মকোইটা সত্যাপন কৰা ঃ 

(i) a + b = b + a

Solution: 16 + (-22) = (-22) + 16 

       16 – 22 = (-22) +16

       -6 = – 6 

(ii) (a + b) + c = a + (b + c) 

Solution: {16 + (-22)} + 18 = {16 + (-22)} + 18

        ( 16 – 22) + 18 = (16 -22 ) +18 

        -6 + 18 = -6 + 18

        12 = 12

(iii) a +0 = a 

Solution: 16 + 0 = 16 

         16 = 16 

(iv) 0 + b = b 

Solution: 0 + (-22) = – 22

        0 – 22 = -22

        -22 = -22 

(v) a – b ≠ b – a 

Solution:  16 – (-22) = -22 – 16 

        16 + 22 = -22 – 16 

        38 = -38

∴ 38 ≠ -38

(vi) (a – b) – c ≠ a -(b -c) 

Solution: { 16 – (-22)} – 18 =  16 – (-22 -18) 

         (16 + 22) – 18 = 16 – (-22 -18 )

         38 -18 = 16 – (-40) 

         38 – 18 = 16 + 40

         20 = 56 

∴ 20 ≠ 56 

Type: Pompi Hazarika